JEE Advance - Chemistry (2022 - Paper 2 Online - No. 11)
The compound(s) which react(s) with $\mathrm{NH}_{3}$ to give boron nitride (BN) is(are)
$\mathrm{B}$
$\mathrm{B}_{2} \mathrm{H}_{6}$
$\mathrm{B}_{2} \mathrm{O}_{3}$
$\mathrm{HBF}_{4}$
Explanation
The compound(s) which react with $\mathrm{NH}_3$ to form Boron nitride $(\mathrm{BN})$ is/are:
(A) Amorphous $\mathrm{B}+\mathrm{NH}_3 \underset{\text { Tempreature }}{\stackrel{\text { Very high }}{\longrightarrow}} \mathrm{BN}+\mathrm{H}_2$
(B) $\mathrm{B}_2 \mathrm{H}_6+\mathrm{NH}_3 \stackrel{\text { High Temp. }}{\longrightarrow}(\mathrm{BN})_{\mathrm{x}}$
(C) $\mathrm{B}_2 \mathrm{O}_3+2 \mathrm{NH}_3 \stackrel{900^{\circ} \mathrm{C}}{\longrightarrow} 2 \mathrm{BN}+3 \mathrm{H}_2 \mathrm{O}$
(D) $\mathrm{HBF}_4+\mathrm{NH}_3 \longrightarrow\left[\mathrm{NH}_4^{\oplus}\right]\left[\mathrm{BF}_4^{\ominus}\right]$
Hence, $(A, B, C)$ are correct
(A) Amorphous $\mathrm{B}+\mathrm{NH}_3 \underset{\text { Tempreature }}{\stackrel{\text { Very high }}{\longrightarrow}} \mathrm{BN}+\mathrm{H}_2$
(B) $\mathrm{B}_2 \mathrm{H}_6+\mathrm{NH}_3 \stackrel{\text { High Temp. }}{\longrightarrow}(\mathrm{BN})_{\mathrm{x}}$
(C) $\mathrm{B}_2 \mathrm{O}_3+2 \mathrm{NH}_3 \stackrel{900^{\circ} \mathrm{C}}{\longrightarrow} 2 \mathrm{BN}+3 \mathrm{H}_2 \mathrm{O}$
(D) $\mathrm{HBF}_4+\mathrm{NH}_3 \longrightarrow\left[\mathrm{NH}_4^{\oplus}\right]\left[\mathrm{BF}_4^{\ominus}\right]$
Hence, $(A, B, C)$ are correct
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