JEE Advance - Chemistry (2022 - Paper 1 Online - No. 16)

LIST-I contains compounds and LIST-II contains reactions

List-I List-II
(I) $\mathrm{H}_{2} \mathrm{O}_{2}$
(P) $\mathrm{Mg}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$
(II) $\mathrm{Mg}(\mathrm{OH})_{2}$
(Q) $\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow$
(III) $\mathrm{BaCl}_{2}$
(R) $\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{MgCl}_{2} \rightarrow$
(IV) $\mathrm{CaCO}_{3}$
(S) $\mathrm{BaO}_{2}+\mathrm{HCl} \rightarrow$
(T) $\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$

Match each compound in LIST-I with its formation reaction(s) in LIST-II, and choose the correct option

I $\rightarrow$ Q; II $\rightarrow$ P; III $\rightarrow$ S; IV $\rightarrow$ R
I $\rightarrow$ T; II $\rightarrow$ P; III $\rightarrow$ Q; IV $\rightarrow$ R
I $\rightarrow$ T; II $\rightarrow$ R; III $\rightarrow$ Q; IV $\rightarrow$ P
I $\rightarrow$ Q; II $\rightarrow$ R; III $\rightarrow$ S; IV $\rightarrow$ P

Explanation

(P) $\mathrm{Mg}\left(\mathrm{HCO}_3\right)_2+\mathrm{Ca}(\mathrm{OH})_2 \rightarrow \mathrm{Mg}(\mathrm{OH})_2+\mathrm{CaCO}_3+\mathrm{H}_2 \mathrm{O}$

(Q) $\mathrm{BaO}_2+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{BaSO}_4+\mathrm{H}_2 \mathrm{O}_2$

(R) $\mathrm{Ca}(\mathrm{OH})_2+\mathrm{MgCl}_2 \rightarrow \mathrm{Mg}(\mathrm{OH})_2+\mathrm{CaCl}_2$

(S) $\mathrm{BaO}_2+\mathrm{HCl} \rightarrow \mathrm{BaCl}_2+\mathrm{H}_2 \mathrm{O}_2$

(T) $\mathrm{Ca}\left(\mathrm{HCO}_3\right)_2+\mathrm{Ca}(\mathrm{OH})_2 \rightarrow 2 \mathrm{CaCO}_3+2 \mathrm{H}_2 \mathrm{O}$

Ans. $\quad \mathrm{I} \rightarrow \mathrm{Q}, \mathrm{S} ; \mathrm{II} \rightarrow \mathrm{P}, \mathrm{R} ; \mathrm{III} \rightarrow \mathrm{S} ; \mathrm{IV} \rightarrow \mathrm{P}, \mathrm{T}$

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