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JEE Advance - Chemistry (2021 - Paper 2 Online - No. 16)

The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
Among the following, the brown ring is due to the formation of
[Fe(NO)2](SO4)2]2$$-$$
[Fe(NO)2](H2O)4]3+
[Fe(NO)4](SO4)2]
[Fe(NO)(H2O)5]2+

Explanation

Brown ring is due to the formation of [Fe(NO)(H2O)5]2+
JEE Advanced 2021 Paper 2 Online Chemistry - Salt Analysis Question 21 English Explanation

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