JEE Advance - Chemistry (2021 - Paper 1 Online - No. 11)
Given :
The compound(s), which on reaction with HNO3 will give the product having degree of rotation, [$$\alpha$$]D = $$-$$52.7$$^\circ$$ is (are)
The compound(s), which on reaction with HNO3 will give the product having degree of rotation, [$$\alpha$$]D = $$-$$52.7$$^\circ$$ is (are)
Explanation
Monosaccharide oxidises on reacting with HNO3 to form carboxylic acids. Primary alcohols also oxidise to carboxylic acid alongwith aldehyde.
Complete reaction is as follows :
The enantiomer of product (P) has rotation −52.7o . The two enantiomers (c and d) with their reactions are as follows :
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