JEE Advance - Chemistry (2019 - Paper 2 Offline - No. 6)
Choose the correct option(s) from the following.
Teflon is prepared by heating tetrafluoroethene in presence of a persulphate catalyst at high pressure.
Natural rubber is polyisoprene containing trans alkene units
Cellulose has only $$\alpha $$-D-glucose units that are joined by glycosidic linkages
Nylon-6 has amide linkages
Explanation
(a) Teflon is prepared by heating tetrafluoroethene in presence of persulphate catalyst at higher pressure.
Thus, option (a) is correct.
(b) Natural rubber is a linear polymer of isoprene (2-methyl-1,3-butadiene) also known as cis-1,4-polyisoprene.
Thus, option (b) is incorrect.
(c) Cellulose has only $$\beta $$-D-glucose units that are joined together by glycosidic linkages as shown in the following structure :
Thus, option (c) is incorrect.
(d) Nylon-6 has amide linkages.
Thus, option (d) is correct.
Thus, option (a) is correct.
(b) Natural rubber is a linear polymer of isoprene (2-methyl-1,3-butadiene) also known as cis-1,4-polyisoprene.
Thus, option (b) is incorrect.
(c) Cellulose has only $$\beta $$-D-glucose units that are joined together by glycosidic linkages as shown in the following structure :
Thus, option (c) is incorrect.
(d) Nylon-6 has amide linkages.
Thus, option (d) is correct.
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