JEE Advance - Chemistry (2019 - Paper 2 Offline - No. 15)
Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following List-I contains some quantities for the nth orbit of the atom and List-II contains options showing how they depend on n.
Which of the following options has the correct combination considering List-I and List-II?
Which of the following options has the correct combination considering List-I and List-II?
(III), (P)
(III), (S)
(IV), (U)
(IV), (Q)
Explanation
(III) Kinetic energy of the electron in nth orbit,
$$K.E. = + 13.6 \times {{{Z^2}} \over {{n^2}}}$$ or $$K.E. \propto {1 \over {{n^2}}}$$ or $$K.E. \propto {n^{ - 2}}$$
From List-II, correct match is (III, P)
(IV) Potential energy of the electron in the nth orbit,
$$P.E. = - 2 \times 13.6 \times {{{Z^2}} \over {{n^2}}} \Rightarrow P.E. \propto {1 \over {{n^2}}} \Rightarrow P.E. \propto {n^{ - 2}}$$
From List-II, correct match is (IV, P).
Hence, correct matching from List-I and List-II on the basis of given options is (III, P).
$$K.E. = + 13.6 \times {{{Z^2}} \over {{n^2}}}$$ or $$K.E. \propto {1 \over {{n^2}}}$$ or $$K.E. \propto {n^{ - 2}}$$
From List-II, correct match is (III, P)
(IV) Potential energy of the electron in the nth orbit,
$$P.E. = - 2 \times 13.6 \times {{{Z^2}} \over {{n^2}}} \Rightarrow P.E. \propto {1 \over {{n^2}}} \Rightarrow P.E. \propto {n^{ - 2}}$$
From List-II, correct match is (IV, P).
Hence, correct matching from List-I and List-II on the basis of given options is (III, P).
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