JEE Advance - Chemistry (2019 - Paper 1 Offline - No. 5)
Choose the reaction(s) from the following options, for which the standard enthalpy of reaction of equal to the standard enthalpy of formation.
2C(g) + 3H2(g) $$ \to $$ C2H6(g)
2H2(g) + O2(g) $$ \to $$ 2H2O(l)
$${3 \over 2}$$O2(g) $$ \to $$ O3(g)
$${1 \over 8}$$S8(s) + O2(g) $$ \to $$ SO2(g)
Explanation
The standard enthalpy of formation is defined as standard enthalpy change for formation of 1 mole of a substance from its elements, present in their most stable state of aggregation.
$${3 \over 2}$$O2(g) $$ \to $$ O3(g);
$${1 \over 8}$$S8(s) + O2(g) $$ \to $$ SO2(g)
In the above two reactions standard enthalpy of reaction is equal to standard enthalpy of formation.
$${3 \over 2}$$O2(g) $$ \to $$ O3(g);
$${1 \over 8}$$S8(s) + O2(g) $$ \to $$ SO2(g)
In the above two reactions standard enthalpy of reaction is equal to standard enthalpy of formation.
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