JEE Advance - Chemistry (2018 - Paper 2 Offline - No. 4)
$${N_2}{O_3},{N_2}{O_5},$$ $${P_4}{O_6},{P_4}{O_7},$$ $${H_4}{P_2}{O_5},{H_5}{P_3}{O_{10}},$$ $${H_2}{S_2}{O_3},{H_2}{S_2}{O_5}$$
Explanation
The structures of various molecules given in problem are discussed below -
1. N2O3 It is the tautomeric mixture of following two structures -
Conclusion 1 bridging oxo group is present in the compound.
2. N2O5 It has following structure.
Conclusion 1 bridging oxo group is present in the compound.
where, pi = initial pressure, pt = total pressure, y = number of gaseous products per mole of reactant
3. P4O6
Conclusion 6 bridging oxo groups are present in the compound.
4. P4O7
Conclusion 6 bridging oxo groups are present in the compound.
5. H4P2O5
Conclusion 1 bridging oxo group is present in the compound.
6. H5P3O10
Conclusion 2 bridging oxo groups are present in the compound.
7. H2S2O3
Conclusion This compound does not contain any bridging oxo group.
8. H2S2O5
Conclusion This compound also does not contain any bridging oxo group.
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