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JEE Advance - Chemistry (2017 - Paper 2 Offline - No. 7)

The reaction of compound $$P$$ with $$C{H_3}MgBr$$ (excess) in $${\left( {{C_2}{H_5}} \right)_2}O$$ followed by addition of $${H_2}O$$ gives $$Q.$$ The compound $$Q$$ on treatment with $${H_2}S{O_4}$$ at $${0^ \circ }C$$ gives $$R.$$ The reaction of $$R$$ with $$C{H_3}COCl$$ in the presence of anhydrous $$AlC{l_3}$$ in $$C{H_2}C{l_2}$$ followed by treatment with $${H_2}O$$ producess compound $$S.$$ [$$Et$$ in compound $$P$$ is ethyl group]

The reaction of compound $$P$$ with $$C{H_3}MgBr$$ (excess) in $${\left( {{C_2}{H_5}} \right)_2}O$$ followed by addition of $${H_2}O$$ gives $$Q.$$ The compound $$Q$$ on treatment with $${H_2}S{O_4}$$ at $${0^ \circ }C$$ gives $$R.$$ The reaction of $$R$$ with $$C{H_3}COCl$$ in the presence of anhydrous $$AlC{l_3}$$ in $$C{H_2}C{l_2}$$ followed by treatment with $${H_2}O$$ producess compound $$S.$$ [$$Et$$ in compound $$P$$ is ethyl group]

The reaction of compound $$P$$ with $$C{H_3}MgBr$$ (excess) in $${\left( {{C_2}{H_5}} \right)_2}O$$ followed by addition of $${H_2}O$$ gives $$Q.$$ The compound $$Q$$ on treatment with $${H_2}S{O_4}$$ at $${0^ \circ }C$$ gives $$R.$$ The reaction of $$R$$ with $$C{H_3}COCl$$ in the presence of anhydrous $$AlC{l_3}$$ in $$C{H_2}C{l_2}$$ followed by treatment with $${H_2}O$$ producess compound $$S.$$ [$$Et$$ in compound $$P$$ is ethyl group]

The reactions, $$Q$$ to $$R$$ and $$R$$ to $$S,$$ are
Dehydration and Friedel$$-$$Crafts acylation
Aromatic sulfonation and Friedel$$-$$Crafts acylation
Friedel$$-$$Crafts alkylation, dehydration and Friedel$$-$$Crafts acylation
Friedel$$-$$Crafts alkylation and Friedel$$-$$Crafts acylation

Explanation

The reaction $\mathrm{Q} \rightarrow \mathrm{R}$ and $\mathrm{R} \rightarrow \mathrm{S}$ Friedel-Crafts alkylation and Friedel-Crafts alkylation is the introduction of alkyl group into benzene ring in presence of lewis acid catalyst such as anhydrous $\mathrm{AlCl}_3$. Friedel Crafts acylation is the introduction of acyl group into benzene ring in presence of lewis acid catalyst such as anhydrous $\mathrm{AlCl}_3$.

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