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JEE Advance - Chemistry (2017 - Paper 2 Offline - No. 6)

Upon heating $$KCl{O_3}$$ in the presence of catalytic amount of $$Mn{O_2},$$ a gas $$W$$ is formed. Excess amount of $$W$$ reacts with white phosphorous to give $$X.$$ The reaction of $$X$$ with pure $$HN{O_3}$$ gives $$Y$$ and $$Z.$$
Upon heating $$KCl{O_3}$$ in the presence of catalytic amount of $$Mn{O_2},$$ a gas $$W$$ is formed. Excess amount of $$W$$ reacts with white phosphorous to give $$X.$$ The reaction of $$X$$ with pure $$HN{O_3}$$ gives $$Y$$ and $$Z.$$
Upon heating $$KCl{O_3}$$ in the presence of catalytic amount of $$Mn{O_2},$$ a gas $$W$$ is formed. Excess amount of $$W$$ reacts with white phosphorous to give $$X.$$ The reaction of $$X$$ with pure $$HN{O_3}$$ gives $$Y$$ and $$Z.$$
$$W$$ and $$X$$ are, respectively
$${O_3}$$ and $${P_4}{O_6}$$
$${O_2}$$ and $${P_4}{O_6}$$
$${O_2}$$ and $${P_4}{O_{10}}$$
$${O_3}$$ and $${P_4}{O_{10}}$$

Explanation

(i) Potassium chlorate $\left(\mathrm{KClO}_3\right)$ is decomposed in presence of $\mathrm{MnO}_2$ as catalyst to form potassium chloride and oxygen gas.

$2 \mathrm{KClO}_3(s) \underset{\mathrm{MnO}_2}{\stackrel{\Delta}{\longrightarrow}} 2 \mathrm{KCl}+\underset{(w)}{3 \mathrm{O}_2(g)}$

The gas $(w)$ is oxygen.

(ii) Reaction of white phosphorous with excess of gas $w$ (i.e., $\mathrm{O}_2$ ) gives $\mathrm{P}_4 \mathrm{O}_{10}$ (a dimer of phosphorous pentaoxide).

$$ \underset{\text{White}}{\mathrm{P}_4(s)}+\underset{\text{(excess)}}{5 \mathrm{O}_2(g)} \rightarrow \underset{(X)}{\mathrm{P}_4 \mathrm{O}_{10}(s)}$$

phosphorous oxygen

The compound $(X)$ is $\mathrm{P}_4 \mathrm{O}_{10}$.

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