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JEE Advance - Chemistry (2017 - Paper 2 Offline - No. 2)

Upon heating $$KCl{O_3}$$ in the presence of catalytic amount of $$Mn{O_2},$$ a gas $$W$$ is formed. Excess amount of $$W$$ reacts with white phosphorous to give $$X.$$ The reaction of $$X$$ with pure $$HN{O_3}$$ gives $$Y$$ and $$Z.$$
Upon heating $$KCl{O_3}$$ in the presence of catalytic amount of $$Mn{O_2},$$ a gas $$W$$ is formed. Excess amount of $$W$$ reacts with white phosphorous to give $$X.$$ The reaction of $$X$$ with pure $$HN{O_3}$$ gives $$Y$$ and $$Z.$$
Upon heating $$KCl{O_3}$$ in the presence of catalytic amount of $$Mn{O_2},$$ a gas $$W$$ is formed. Excess amount of $$W$$ reacts with white phosphorous to give $$X.$$ The reaction of $$X$$ with pure $$HN{O_3}$$ gives $$Y$$ and $$Z.$$
$$Y$$ and $$Z$$ are, respectively
$${N_2}{O_3}$$ and $${H_3}P{O_4}$$
$${N_2}{O_5}$$ and $$HP{O_3}$$
$${N_2}{O_4}$$ and $$HP{O_3}$$
$${N_2}{O_4}$$ and $${H_3}P{O_3}$$

Explanation

Reaction of $\mathrm{P}_4 \mathrm{O}_{10}$ with pure nitric acid $\left(\mathrm{HNO}_3\right)$ gives dinitrogen pentaoxide $\left(\mathrm{N}_2 \mathrm{O}_5\right)$ and metaphosphoric acid $\left(\mathrm{HPO}_3\right)$

$$ \mathrm{P}_4 \mathrm{O}_{10}+4 \mathrm{HNO}_3 \rightarrow \underset{Z}{4 \mathrm{HPO}_3}+\underset{Y}{2 \mathrm{~N}_2 \mathrm{O}_5} $$

The compound $\mathrm{Y}$ is dinitrogen pentaoxide $\left(\mathrm{N}_2 \mathrm{O}_5\right)$ and compound $\mathrm{Z}$ is metaphosphoric $\operatorname{acid}\left(\mathrm{HPO}_3\right)$.

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