JEE Advance - Chemistry (2017 - Paper 1 Offline - No. 15)

Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK
(R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK
(R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK
(R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
The only CORRECT combination that gives two different carboxylic acids is :
(II) (iv) (R)
(IV) (iii) (Q)
(III) (iii) (P)
(I) (i) (S)

Explanation

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 1
Reaction of benzaldehyde with acetic anhydride in presence of potassium acetate results in formation of cinnamic acid. Cinnamic acid contains cis and trans forms; hence, two types of acids are generated. This is called Perkin reaction.

Mechanism of Perkin reaction is as follows :

(i) The potassium acetate is a strong base and abstracts acidic $\alpha$-proton from acetic anhydride.

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 2
(ii) The negatively charged carbanion attacks the carbon of carbonyl group of benzaldehyde.

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 3 JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 4

(iii) The intermediate formed undergoes rearrangement

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 5
(iv) Loss of proton from $\alpha$-carbon gives cinnamic acid

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 6 JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 7

(v) Depending upon the orientation of carboxylic functional group cis and trans cinnamic acid are formed.

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 62 English Explanation 8

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