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JEE Advance - Chemistry (2017 - Paper 1 Offline - No. 14)

Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK		 (R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK		 (R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK		 (R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
The only CORRECT combination in which the reaction proceeds through radical mechanism is :
(III) (ii) (P)
(IV) (i) (Q)
(II) (iii) (R)
(I) (ii) (R)

Explanation

The following reaction takes place by free radical mechanism :

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 61 English Explanation 1
The mechanism is as follows :

JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 61 English Explanation 2 JEE Advanced 2017 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 61 English Explanation 3

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