JEE Advance - Chemistry (2015 - Paper 1 Offline - No. 19)
Fe3+ is reduced to Fe2+ by using
H2O2 in presence of NaOH.
Na2O2 in water.
H2O2 in presence of H2SO4.
Na2O2 in presence of H2SO4.
Explanation
Fe3+ is reduced to Fe2+ by H2O2/NaOH and Na2O2/H2O.
$$2F{e^{3 + }} + {H_2}{O_2} + O{H^ - } \to 2F{e^{2 + }} + 2{H_2}O + {O_2}$$
$$N{a_2}{O_2} + {H_2}O \to {H_2}{O_2} + NaOH$$
Comments (0)
