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JEE Advance - Chemistry (2014 - Paper 2 Offline - No. 16)

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

Reagent S is
K4[Fe(CN)6]
Na2HPO4
K2CrO4
KOH

Explanation

The reaction involved is

Zn2+ + OH$$-$$ $$\to$$ Zn(OH)2 $$\buildrel {O{H^ - }} \over \longrightarrow $$ [Zn(OH)4]2$$-$$ (soluble)

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