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JEE Advance - Chemistry (2014 - Paper 2 Offline - No. 15)

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

M1, Q and R, respectively, are
Zn2+, KCN and HCl
Ni2+, HCl and KCN
Cd2+, KCN and HCl
Co2+, HCl and KCN

Explanation

The reactions involved are

$$N{i^{2 + }} + HCl \to \mathop {{{\left[ {NiC{l_4}} \right]}^2}}\limits_{Tetrahedral} $$

$$N{i^{2 + }} + KCN \to \mathop {{{\left[ {Ni{{(CN)}_4}} \right]}^{2 - }}}\limits_{Square\,planar} $$

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