JEE Advance - Chemistry (2013 - Paper 2 Offline - No. 15)

A fixed mass m of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.

A fixed mass m of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.

A fixed mass m of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.

The succeeding operations that enable this transformation of states are
Heating, cooling, heating, cooling.
Cooling, heating, cooling, heating.
Heating, cooling, cooling, heating.
Cooling, heating, heating, cooling.

Explanation

From the graph, as the term pV increases, the temperature increases; and when pV decreases the temperature decreases.

JEE Advanced 2013 Paper 2 Offline Chemistry - Thermodynamics Question 16 English Explanation

The term PV increases K$$\to$$L, so this involves heating and is an isobaric process.

It increases from N$$\to$$K, so this involves heating and is an isochoric process.

It decreases from M$$\to$$N, so this involves cooling and is an isobaric process.

It decreases from L$$\to$$M, so this involves cooling and is an isochoric process.

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