JEE Advance - Chemistry (2012 - Paper 2 Offline - No. 7)
The reaction of white phosphorous with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product are, respectively,
redox reaction; $$-$$3 and $$-$$5
redox reaction; +3 and +5
disproportionation reaction; $$-$$3 and +1
disproportionation reaction; $$-$$3 and +3
Explanation
According to the reaction
P4 + NaOH + 3H2O $$\to$$ PH3 + 3NaH2PO2
oxidation state of phosphorus in P4 is zero while in PH3 it is $$-$$3 and in NaH2PO2, it is +1. This shows that this is a type of disproportionation reaction because there is an increase as well as decrease in the oxidation state of phosphorus.
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