JEE Advance - Chemistry (2011 - Paper 2 Offline - No. 18)
The volume (in mL) of 0.1 M AgNO3 required for complete precipitation of chloride ions present in 30 mL of 0.01 M solution of $$[Cr{({H_2}O)_5}Cl]C{l_2}$$, as silver chloride is close to ____________.
Answer
6
Explanation
The reaction taking place is
$$2AgN{O_3} + [Cr{({H_2}O)_5}Cl]C{l_2} \to 2AgCl + [Cr{({H_2}O)_5}Cl]{(N{O_3})_2}$$
Using molarity equation
$${(M \times n \times V)_{AgN{O_3}}} = {(M \times n \times V)_{[Cr{{({H_2}O)}_5}Cl]C{l_2}}}$$
$$0.1 \times 1 \times V = 0.01 \times 2 \times 30 \Rightarrow V = 6$$
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