JEE Advance - Chemistry (2010 - Paper 2 Offline - No. 19)

All the compounds listed in Column I react with water. Match the result of the respective reactions with the appropriate options listed in Column II.

Column I Column II
(A) (CH3)2SiCl2 (P) Hydrogen halide formation
(B) XeF4 (Q) Redox reaction
(C) Cl2 (R) Reacts with glass
(D) VCl5 (S) Polymerisation
(T) O2 formation
(A)→(P); (B)→(P), (Q), (R), (T); (C)→(P); (D)→(P)
(A)→(P), (S); (B)→(P), (Q), (R), (T); (C)→(P), (Q); (D)→(P)
(A)→(P), (S); (B)→(P), (R), (T); (C)→(P), (Q); (D)→(P)
(A)→(P), (S); (B)→(P), (Q), (R); (C)→(P), (Q); (D)→(P)

Explanation

(A) Dimethyl silyl chloride undergoes hydration followed by polymerisation owing to the loss of water molecule.

IIT-JEE 2010 Paper 2 Offline Chemistry - p-Block Elements Question 1 English Explanation

(A) → P, S

$$ \begin{aligned} & \text { (B) } 6 \mathrm{XeF}_4+12 \mathrm{H}_2 \mathrm{O} \rightarrow 4 \mathrm{Xe}+2 \mathrm{XeO}_3 +24 \mathrm{HF} \text { (Hydrogen fluoride) }+3 \mathrm{O}_2 \text { (Oxygen) } \\ & \end{aligned} $$

Here, xenon undergoes disproportionation reaction (which is a kind of redox reaction) with xenon (in +4 oxidation state) gets oxidized to xenon trioxide $\left(\mathrm{XeO}_3\right)$ and reduced to xenon (Xe) at the same time.

HF reacts with glass as shown :

$$ \mathrm{Na}_2 \mathrm{SiO}_3+6 \mathrm{HF} \rightarrow \mathrm{Na}_2 \mathrm{SiF}_6+3 \mathrm{H}_2 \mathrm{O} $$

(B) → P, Q, R, T

(C)

$2 \mathrm{Cl}_2+2 \mathrm{H}_2 \mathrm{O} \longrightarrow {4 \mathrm{HCl} \text { (Hydrogen } \text { halide )}+\mathrm{O}_2}$

(C) $\rightarrow$ P, Q

(D) $\mathrm{VCl}_5+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{VOCl}_3+2 \mathrm{HCl}$ (Hydrogen chloride)

(D) $\rightarrow P$

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