JEE Advance - Chemistry (2009 - Paper 2 Offline - No. 10)
Match each of the reactions given in Column I with the corresponding product(s) given in Column II:
| Column I | Column II | ||
|---|---|---|---|
| (A) | $$\mathrm{Cu+dil.~HNO_3}$$ | (P) | $$\mathrm{NO}$$ |
| (B) | $$\mathrm{Cu+conc.~HNO_3}$$ | (Q) | $$\mathrm{NO_2}$$ |
| (C) | $$\mathrm{Zn+dil.~HNO_3}$$ | (R) | $$\mathrm{N_2O}$$ |
| (D) | $$\mathrm{Zn+conc.~HNO_3}$$ | (S) | $$\mathrm{Cu(NO_3)_2}$$ |
| (T) | $$\mathrm{Zn(NO_3)_2}$$ |
(A)$$\to$$(P), (S); (B)$$\to$$(R), (S); (C)$$\to$$(R), (T); (D)$$\to$$(R), (T)
(A)$$\to$$(T), (S); (B)$$\to$$(P), (S); (C)$$\to$$(R), (T); (D)$$\to$$(S), (T)
(A)$$\to$$(P), (S); (B)$$\to$$(Q), (S); (C)$$\to$$(R), (T); (D)$$\to$$(Q), (T)
(A)$$\to$$(R), (S); (B)$$\to$$(Q), (S); (C)$$\to$$(R), (T); (D)$$\to$$(S), (T)
Explanation
The reactions are as follows:
(A) 3Cu + 8HNO$$_3$$ (dil.) $$\to$$ 3Cu(NO$$_3$$)$$_2$$ + 4H$$_2$$O + 2NO
(B) Cu + 4HNO$$_3$$ (conc.) $$\to$$ Cu(NO$$_3$$)$$_2$$ + 4H$$_2$$O + 2NO$$_2$$
(C) 4Zn + 10HNO$$_3$$ (dil.) $$\to$$ 4Zn(NO$$_3$$)$$_2$$ + 5H$$_2$$O + N$$_2$$O
(D) Zn + HNO$$_3$$ (conc.) $$\to$$ Zn(NO$$_3$$)$$_2$$ + 2H$$_2$$O + 2NO$$_2$$
Comments (0)
