JEE Advance - Chemistry (1998 - No. 8)

Hydrogen peroxide acts both as an oxidising and as a reducing agent in alkaline solution towards certain first row transition metal ions. Illustrate both these properties of H2O2 using chemical equations.
H2O2 can only act as an oxidizing agent in alkaline solutions.
H2O2 can only act as a reducing agent in alkaline solutions.
H2O2 cannot react with transition metal ions in alkaline solutions.
H2O2 can act as both an oxidizing and reducing agent in alkaline solutions, depending on the reactant.
H2O2 always forms hydrogen gas when reacting in alkaline solution.

Explanation

Hydrogen peroxide (H2O2) can act as both an oxidizing agent and a reducing agent, depending on the reactants and the conditions of the reaction. Let's illustrate both properties using chemical equations involving first row transition metal ions.

Hydrogen peroxide as an oxidizing agent:

In an alkaline solution, hydrogen peroxide can oxidize manganese(II) ions (Mn2+) to manganese dioxide (MnO2). The balanced chemical equation for this reaction is:

$$2\text{Mn}^{2+} + \text{H}_2\text{O}_2 + 4\text{OH}^- \rightarrow 2\text{MnO}_2 + 4\text{H}_2\text{O}$$

In this reaction, H2O2 is reduced to water (H2O), while Mn2+ is oxidized to MnO2.

Hydrogen peroxide as a reducing agent:

Conversely, in an alkaline solution, hydrogen peroxide can reduce chromium(VI) ions (CrO42-) to chromium(III) ions (Cr3+). The balanced chemical equation for this reaction is:

$$2\text{CrO}_4^{2-} + 3\text{H}_2\text{O}_2 + 2\text{OH}^- \rightarrow 2\text{Cr}^{3+} + 3\text{O}_2 + 5\text{H}_2\text{O}$$

In this reaction, H2O2 is oxidized to oxygen (O2), while CrO42- is reduced to Cr3+.

Through these equations, it is clear that hydrogen peroxide can exhibit both oxidizing and reducing properties in alkaline solutions, depending on the nature of the transition metal ion it interacts with. These dual roles make H2O2 a versatile reagent in various chemical processes.

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