JEE Advance - Chemistry (1989 - No. 2)

An equal volume of a reducing agent is titrated separately with 1M KMnO4 in acid neutral and alkaline media. The volumes of KMnO4 required are 20 ml. in acid 33.4 ml. neutral and 100 ml in alkaline media. Find out the oxidation state of manganese in each reduction product. Give the balanced equations for all three half reactions. Find out the volume of 1M K2Cr2O7 consumed; if the same volume of the reducing agent is titrated in acid medium.
The oxidation states of manganese are +2, +4, +6 and the volume of K2Cr2O7 is 16.66 ml
The oxidation states of manganese are +1, +3, +5 and the volume of K2Cr2O7 is 10.00 ml
The oxidation states of manganese are +3, +5, +7 and the volume of K2Cr2O7 is 20.00 ml
The oxidation states of manganese are +2, +4, +6 and the volume of K2Cr2O7 is 20.00 ml
The oxidation states of manganese are +1, +3, +5 and the volume of K2Cr2O7 is 16.66 ml

Comments (0)

Advertisement