JEE Advance - Chemistry (1981 - No. 5)

Balance the following Equations:

(i) Cu₂O + H⁺ + $$NO_3^ - \to $$ Cu²⁺ + NO + H₂O

(ii) K₄[Fe(CN)₆] + H₂SO₄ + H₂O $$\to$$ K₂SO₄ + FeSO₄ + (NH₄)₂SO₄ + CO

(iii) C2H5OH + I₂ + OH^- $$\to$$ CHI₃ + $$HCO_3^-$$ + I^- + 4H₂O

For (i): 3Cu₂O + 14H⁺ + 2NO₃^- → 6Cu²⁺ + 2NO + 7H₂O, For (ii): K₄[Fe(CN)₆] + 6H₂SO₄ + 6H₂O → 2K₂SO₄ + FeSO₄ + 3(NH₄)₂SO₄ + 6CO, For (iii): C₂H₅OH + 4I₂ + 6OH^- → CHI₃ + HCO₃^- + 5I^- + 5H₂O

For (i): 2Cu₂O + 10H⁺ + NO₃^- → 4Cu²⁺ + NO + 5H₂O, For (ii): K₄[Fe(CN)₆] + 5H₂SO₄ + 5H₂O → 2K₂SO₄ + FeSO₄ + 2(NH₄)₂SO₄ + 6CO, For (iii): C₂H₅OH + 3I₂ + 4OH^- → CHI₃ + HCO₃^- + 3I^- + 3H₂O

For (i): 3Cu₂O + 14H⁺ + 2NO₃^- → 6Cu²⁺ + 2NO + 7H₂O, For (ii): K₄[Fe(CN)₆] + 6H₂SO₄ + 6H₂O → 2K₂SO₄ + FeSO₄ + 3(NH₄)₂SO₄ + 6CO, For (iii): C₂H₅OH + 4I₂ + 8OH^- → CHI₃ + HCO₃^- + 5I^- + 6H₂O

For (i): 3Cu₂O + 10H⁺ + 2NO₃^- → 6Cu²⁺ + NO + 5H₂O, For (ii): K₄[Fe(CN)₆] + 5H₂SO₄ + 6H₂O → 2K₂SO₄ + FeSO₄ + 3(NH₄)₂SO₄ + 5CO, For (iii): C₂H₅OH + 4I₂ + 7OH^- → CHI₃ + HCO₃^- + 4I^- + 6H₂O

For (i): Cu₂O + H⁺ + NO₃^- → Cu²⁺ + NO + H₂O, For (ii): K₄[Fe(CN)₆] + H₂SO₄ + H₂O → K₂SO₄ + FeSO₄ + (NH₄)₂SO₄ + CO, For (iii): C2H5OH + I₂ + OH^- → CHI₃ + HCO₃^- + I^- + H₂O

JEE Advance - Chemistry (1981 - No. 5)

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