JEE Advance - Chemistry (1979 - No. 12)

Account for the following : Limit your answer to two sentences.

"Atomic weights of most of the elements are fractional."

The atomic weights are determined experimentally and the experimental setup is faulty.
The atomic weights are the average mass of isotopes, and most elements have isotopes with non-integer masses.
The atomic weights are average weights of the element which accounts for the relative abundance of its isotopes, thus yielding fractional values.
The atomic weights were originally measured relative to hydrogen, and the measurement was not precise.
The atomic weights are calculated by dividing the mass number of the element by the number of protons, leading to non-integer values.

Explanation

Most of the naturally occurring elements occurs in the form of isotopes and if different isotopes present in the element are significant in quantity then by calculating their weighted average we get fractional atomic weight.

Note that in question it is given that most of the element's atomic weight is fractional not all elements. Because for example atomic weight of Cl = 35.5 which is fractional but atomic weight of C = 12 which is integer. That is why we can't say all element's atomic weight is fractional. The reason is explained below $$\to$$

Naturally available two isotopes of Cl are 75% $${}_{17}C{l^{35}}$$ and 25% $${}_{17}C{l^{37}}$$ . Here both isotopes are significantly present inside Cl. So their weighted average depends on both the isotopes. And by calculating we find atomic weight of Cl = 35.5 (It is a fraction). There are 3 main naturally available isotopes of Carbon (1) 98.9% $${}_6{C^{12}}$$ (2) 1.1% $${}_6{C^{13}}$$ and (3) 0.0001% $${}_6{C^{14}}$$ . As $${}_6{C^{13}}$$ and $${}_6{C^{14}}$$ are negligible compared to $${}_6{C^{12}}$$ . So their weighted average depends on only $${}_6{C^{12}}$$ . By calculating we find atomic weight of C = 12.0107 $$\simeq$$ 12 (integer)

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