JEE Advance - Chemistry (1978 - No. 2)
Explanation
The correct answer to the question is Option B: CaO.
Let's break down the reasoning:
CaO (Calcium oxide), also known as quicklime, vigorously reacts with water to form calcium hydroxide (Ca(OH)2) and releases a significant amount of heat. This reaction is known as slaking of lime and can be represented as:
$$ \text{CaO} + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 $$
Additionally, calcium oxide has a strong affinity for carbon dioxide (CO2). It absorbs CO2 from the air to form calcium carbonate (CaCO3) through the following reaction:
$$ \text{CaO} + \text{CO}_2 \rightarrow \text{CaCO}_3 $$
Thus, CaO fulfills both conditions: it absorbs CO2 and reacts violently with water. The other substances listed do not meet these criteria:
CaCO3: Calcium carbonate reacts with acids but does not react violently with water and does not absorb CO2.
H2SO4: Sulfuric acid is a liquid that reacts vigorously with water (specifically, dilution of concentrated sulfuric acid is exothermic), but it does not absorb CO2.
ZnO: Zinc oxide is an amphoteric oxide that does not react violently with water and does not absorb CO2.
Therefore, the most appropriate answer is:
Option B: CaO
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