JEE Advance - Chemistry Hindi (2021 - Paper 1 Online - No. 11)

दिया गया है:

JEE Advanced 2021 Paper 1 Online Chemistry - Biomolecules Question 15 Hindi

यौगिक(कों), जो $$\mathrm{HNO}_{3}$$ के साथ अभिक्रिया पर घूर्णन कोण (degree of rotation), $$[\alpha]_{D}=-52.7^{\circ}$$ होने वाला उत्पाद देगा, वो(वें) है(हैं)

JEE Advanced 2021 Paper 1 Online Chemistry - Biomolecules Question 15 Hindi Option 1
JEE Advanced 2021 Paper 1 Online Chemistry - Biomolecules Question 15 Hindi Option 2
JEE Advanced 2021 Paper 1 Online Chemistry - Biomolecules Question 15 Hindi Option 3
JEE Advanced 2021 Paper 1 Online Chemistry - Biomolecules Question 15 Hindi Option 4

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