JEE MAIN - Physics (2025 - 7th April Morning Shift - No. 8)
A wire of resistance $R$ is bent into a triangular pyramid as shown in figure with each segment having same length. The resistance between points $A$ and $B$ is $R / n$. The value of $n$ is :
_7th_April_Morning_Shift_en_8_1.png)
16
10
12
14
Explanation
As $r=\frac{R}{6}$
_7th_April_Morning_Shift_en_8_2.png)
(As balanced wheat stone bridge is formed) Now, Equivalent resistance between A and B can be written as
$$\begin{aligned} & \frac{1}{\mathrm{R}_{\mathrm{AB}}}=\frac{1}{2 \mathrm{r}}+\frac{1}{2 \mathrm{r}}+\frac{1}{\mathrm{r}}=\frac{2}{\mathrm{r}} \\ & \mathrm{R}_{\mathrm{AB}}=\frac{\mathrm{R}}{12} \end{aligned}$$
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