JEE MAIN - Physics (2025 - 7th April Morning Shift - No. 4)
A rod of length 5 L is bent right angle keeping one side length as 2 L .
_7th_April_Morning_Shift_en_4_1.png)
The position of the centre of mass of the system :
(Consider $\mathrm{L}=10 \mathrm{~cm}$)
$4 \hat{i}+9 \hat{j}$
$2 \hat{i}+3 \hat{j}$
$5 \hat{i}+8 \hat{j}$
$3 \hat{i}+7 \hat{j}$
Explanation
_7th_April_Morning_Shift_en_4_2.png)
$$\begin{aligned} & \mathrm{x}_{\mathrm{com}}=\frac{2 \mathrm{~m}(10)+3 \mathrm{~m}(0)}{5 \mathrm{~m}}=4 \mathrm{~cm} \\ & \mathrm{y}_{\mathrm{com}}=\frac{2 \mathrm{~m}(0)+3 \mathrm{~m}(15)}{5 \mathrm{~m}}=9 \mathrm{~cm} \\ & \overrightarrow{\mathrm{r}}_{\mathrm{com}}=4 \hat{\mathrm{i}}+9 \hat{\mathrm{j}} \end{aligned}$$
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