JEE MAIN - Physics (2025 - 7th April Morning Shift - No. 25)
An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ________ $\times 10^{-1} \mathrm{~J}$. (Take $\pi=3.14$ )
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Answer
314
Explanation
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$$\begin{aligned} &\text { Area of circle, } W=\frac{\pi}{4} d_1 d_2\\ &\begin{aligned} & \mathrm{W}=\frac{\pi}{4}(500-300) \times 10^3(350-150) \times 10^{-6} \\ & \mathrm{~W}=31.4 \mathrm{Joule} \\ & \mathrm{~W}=314 \times 10^{-1} \mathrm{Joule} \end{aligned} \end{aligned}$$
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