JEE MAIN - Physics (2025 - 7th April Morning Shift - No. 24)
A container contains a liquid with refractive index of 1.2 up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 40 cm . The value of H is ________ cm . (Consider liquids are immisible)
Answer
80
Explanation
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$$\begin{aligned} & y=\text { apparent depth of bottom } \\ & \frac{y}{1}=\frac{H}{1.6}+\frac{60}{1.2} \\ & \text { Shift }=40 \\ & H+60-y=40 \\ & H+60-\frac{\mathrm{H}}{1.6}-\frac{60}{1.2}=40 \\ & \frac{6}{16} \mathrm{H}=30 \\ & H=80 \mathrm{~cm} \end{aligned}$$
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