JEE MAIN - Physics (2025 - 7th April Evening Shift - No. 19)

Match List - I with List - II.

List - I List - II
(A) Isothermal (I) ΔW (work done) = 0
(B) Adiabatic (II) ΔQ (supplied heat) = 0
(C) Isobaric (III) ΔU (change in internal energy) ≠ 0
(D) Isochoric (IV) ΔU = 0

Choose the correct answer from the options given below :

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Explanation

To accurately match the terms from List-I with the corresponding statements in List-II, consider the properties of each thermodynamic process:

Isothermal Process (A):

During an isothermal process, the temperature remains constant ($ \Delta T = 0 $), which means that the change in internal energy ($ \Delta U $) is zero. Therefore, it corresponds to (IV).

Adiabatic Process (B):

In an adiabatic process, no heat is exchanged with the surroundings ($ \Delta Q = 0 $). This matches with (II).

Isobaric Process (C):

An isobaric process involves constant pressure conditions ($ \Delta P = 0 $), but internal energy ($ \Delta U $) can change. Thus, it's associated with (III).

Isochoric Process (D):

For an isochoric process, volume remains constant ($ \Delta V = 0 $), which means that no work is done ($ \Delta W = 0 $). This aligns with (I).

Based on these descriptions, the correct matching is:

(A) Isothermal → (IV)

(B) Adiabatic → (II)

(C) Isobaric → (III)

(D) Isochoric → (I)

Comments (0)

Advertisement