JEE MAIN - Physics (2025 - 7th April Evening Shift - No. 16)
Consider the following logic circuit.
_7th_April_Evening_Shift_en_16_1.png)
The output is Y = 0 when :
A = 1 and B = 0
A = 0 and B = 0
A = 1 and B = 1
A = 0 and B = 1
Explanation
_7th_April_Evening_Shift_en_16_2.png)
$$\begin{aligned} & \mathrm{Y}_1=\mathrm{A} \cdot \mathrm{~B}, \mathrm{Y}_2=\overline{\mathrm{A}}+\mathrm{B} \\ & \mathrm{Y}=\overline{\mathrm{Y}_1 \cdot \mathrm{Y}_2}=\overline{\mathrm{Y}}_1+\overline{\mathrm{Y}}_2 \\ & \mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{~B}}+\overline{\overline{\mathrm{A}}+\mathrm{B}} \\ & \mathrm{Y}=\overline{\mathrm{A}}+\overline{\mathrm{B}}+\mathrm{A} \cdot \overline{\mathrm{~B}} \end{aligned}$$
_7th_April_Evening_Shift_en_16_3.png)
Comments (0)
