JEE MAIN - Physics (2025 - 4th April Evening Shift - No. 16)

Match List - I with List - II.

List - I List - II
(A) Isobaric (I) $\Delta Q=\Delta W$
(B) Isochoric (II) $\Delta Q=\Delta U$
(C) Adiabatic (III) $\Delta Q=$ zero
(D) Isothermal (IV) $\Delta Q=\Delta U+P\Delta V$

$\Delta Q=$ Heat supplied

$\Delta W=$ Work done by the system

$\Delta \mathrm{U}=$ Change in internal energy

$\mathrm{P}=$ Pressure of the system

$\Delta \mathrm{V}=$ Change in volume of the system

Choose the correct answer from the options given below :

(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(A)-(II), (B)-(IV), (C)-(III), (D)-(I)

Explanation

(A) Isobaric $(\mathrm{P}=\mathrm{C})$

$$\Delta \mathrm{Q}=\Delta \mathrm{U}+\mathrm{P} \Delta \mathrm{~V}$$

(B) Isochoric $(\mathrm{V}=\mathrm{C})$

$$\Delta \mathrm{Q}=\Delta \mathrm{U}$$

(C) Adiabatic $(\Delta \mathrm{Q}=0)$

$$\Delta \mathrm{Q}=0$$

(D) Isothermal $(\Delta \mathrm{U}=0)$

$$\Delta \mathrm{Q}=\Delta \mathrm{W}$$

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