JEE MAIN - Physics (2025 - 3rd April Evening Shift - No. 12)
$$ \text {The truth table corresponding to the circuit given below is: } $$
_3rd_April_Evening_Shift_en_12_1.png)
$$ \begin{array}{|c|c|c|} \hline \mathrm{A} & \mathrm{~B} & \mathrm{C} \\ \hline 0 & 0 & 0 \\ \hline 0 & 1 & 0 \\ \hline 1 & 0 & 1 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$
$$ \begin{array}{|c|c|c|} \hline \text { A } & \mathrm{B} & \mathrm{C} \\ \hline 0 & 0 & 1 \\ \hline 1 & 0 & 0 \\ \hline 0 & 1 & 0 \\ \hline 1 & 1 & 0 \\ \hline \end{array} $$
$$ \begin{array}{|c|c|c|} \hline \text { A } & \mathrm{B} & \mathrm{C} \\ \hline 0 & 0 & 1 \\ \hline 0 & 1 & 0 \\ \hline 1 & 0 & 0 \\ \hline 1 & 1 & 0 \\ \hline \end{array} $$
$$ \begin{array}{|c|c|c|} \hline \mathrm{A} & \mathrm{~B} & \mathrm{C} \\ \hline 0 & 0 & 0 \\ \hline 1 & 0 & 0 \\ \hline 0 & 1 & 0 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$
Explanation
_3rd_April_Evening_Shift_en_12_2.png)
Comments (0)
