JEE MAIN - Physics (2025 - 2nd April Morning Shift - No. 10)
A square Lamina OABC of length 10 cm is pivoted at ' $\mathrm{O}^{\prime}$. Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of F is :
_2nd_April_Morning_Shift_en_10_1.png)
10 N
0 (zero)
10$\sqrt2$ N
20 N
Explanation
$$\begin{aligned} &\text { Since the lamina is equilibrium. }\\ &\therefore \mathrm{F}_{\text {net }}=0 \& \tau_{\text {net }}=0 \end{aligned}$$
_2nd_April_Morning_Shift_en_10_2.png)
$\mathrm{T}_{\mathrm{o}}=10 \ell-\mathrm{F} \ell \Rightarrow \mathrm{F}=10 \mathrm{~N}$
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