JEE MAIN - Physics (2025 - 2nd April Morning Shift - No. 1)
Consider two infinitely large plane parallel conducting plates as shown below. The plates are uniformly charged with a surface charge density $+\sigma$ and $-2 \sigma$. The force experienced by a point charge +q placed at the mid point between two plates will be:
_2nd_April_Morning_Shift_en_1_1.png)
$\frac{3 \sigma q}{4 \epsilon_0}$
$\frac{3 \sigma \mathrm{q}}{2 \epsilon_0}$
$\frac{\sigma \mathrm{q}}{4 \epsilon_0}$
$\frac{\sigma q}{2 \epsilon_0}$
Explanation
_2nd_April_Morning_Shift_en_1_2.png)
Final charge distribution will be
_2nd_April_Morning_Shift_en_1_3.png)
$\therefore \mathrm{F}_{\mathrm{net}}=\frac{3 \sigma}{2 \epsilon_0} \mathrm{q}$
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