JEE MAIN - Physics (2025 - 2nd April Evening Shift - No. 7)
Two identical objects are placed in front of convex mirror and concave mirror having same radii of curvature of 12 cm , at same distance of 18 cm from the respective mirrors. The ratio of sizes of the images formed by convex mirror and by concave mirror is :
2
$1 / 2$
$1 / 3$
3
Explanation
_2nd_April_Evening_Shift_en_7_1.png)
$$\begin{aligned} & \text { Using } m=\frac{f}{u-f} \\ & m_1=\frac{6}{18-6}=\frac{1}{2} \end{aligned}$$
_2nd_April_Evening_Shift_en_7_2.png)
$\mathrm{m}_2=\frac{6}{18+6}=\frac{1}{4} \quad \therefore \frac{\mathrm{~m}_2}{\mathrm{~m}_1}=\frac{1}{2}$
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