JEE MAIN - Physics (2025 - 2nd April Evening Shift - No. 15)
Explanation
To match the entries in List-I with their corresponding units in List-II, we can use the definitions and formulas related to each concept in thermal physics:
Heat Capacity of a Body (C') is defined as:
$ C' = \frac{\Delta Q}{\Delta T} $
The unit for heat capacity (C') is Joules per Kelvin (J K$^{-1}$).
Specific Heat Capacity of a Body (S) indicates how much heat energy is required to change the temperature of a unit mass of a substance by one degree Kelvin:
$ S = \frac{\Delta Q}{m \Delta T} $
The unit for specific heat capacity (S) is Joules per kilogram per Kelvin (J kg$^{-1}$ K$^{-1}$).
Latent Heat (L) is the heat energy absorbed or released during a phase change of a substance at a constant temperature:
$ L = \frac{\Delta Q}{m} $
The unit for latent heat (L) is Joules per kilogram (J kg$^{-1}$).
Thermal Conductivity (K) measures the ability of a material to conduct heat:
$ \Delta Q = \frac{KA \Delta T}{L} \quad \Rightarrow \quad K = \frac{\Delta Q \cdot L}{A \Delta T} $
The unit for thermal conductivity (K) is Joules per meter per Kelvin per second (J m$^{-1}$ K$^{-1}$ s$^{-1}$).
Using these formulas and their corresponding units, the correct matches are:
(A) Heat capacity of body $\rightarrow$ (II) J K$^{-1}$
(B) Specific heat capacity of body $\rightarrow$ (III) J kg$^{-1}$ K$^{-1}$
(C) Latent heat $\rightarrow$ (I) J kg$^{-1}$
(D) Thermal conductivity $\rightarrow$ (IV) J m$^{-1}$ K$^{-1}$ s$^{-1}$
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