JEE MAIN - Physics (2025 - 29th January Evening Shift - No. 14)
The truth table for the circuit given below is:
_29th_January_Evening_Shift_en_14_1.png)
| A | B | Y |
|---|---|---|
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 0 | 1 |
| 0 | 1 | 1 |
| A | B | Y |
|---|---|---|
| 0 | 0 | 0 |
| 1 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 1 | 0 |
| A | B | Y |
|---|---|---|
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 0 |
| 0 | 1 | 1 |
| A | B | Y |
|---|---|---|
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
Explanation
_29th_January_Evening_Shift_en_14_2.png)
| A | B | $$\overline A $$ | $$\overline B $$ | $$A.\overline B $$ | $$\overline A .B$$ | $\mathrm{Y=A.\bar{B}+\bar{A} . B}$ |
|---|---|---|---|---|---|---|
| 0 | 0 | 1 | 1 | 0 | 0 | 0 |
| 0 | 1 | 1 | 0 | 0 | 1 | 1 |
| 1 | 0 | 0 | 1 | 1 | 0 | 1 |
| 1 | 1 | 0 | 0 | 0 | 0 | 0 |
Hence, option 4 is correct.
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