JEE MAIN - Physics (2025 - 29th January Evening Shift - No. 12)
Match List - I with List - II.
List - I | List - II |
---|---|
(A) Magnetic induction | (I) Ampere meter2 |
(B) Magnetic intensity | (II) Weber |
(C) Magnetic flux | (III) Gauss |
(D) Magnetic moment | (IV) Ampere meter |
Choose the correct answer from the options given below:
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
Explanation
(A) The unit "gauss" is used to measure magnetic induction, also known as magnetic flux density, within the CGS system of units.
$$B = {\phi \over A} = {{\max well} \over {c{m^2}}} = gauss\,(CGS)$$
(B) Magnetic intensity (H) is defined as the product of the number of turns per unit length in a coil (n) and the current that it carries (I).
i.e. $$H = nI = {N \over L}I$$
Unit : A/m or Am$^{-1}$
(C) Magnetic flux, $$\phi = BA$$
unit : weber
(D) Magnetic moment (M) : magnetic moment of a current loop, $$M = NIA$$
where, N = number of turns
I = current
A = Area
So, unit = Am$^2$
Hence, option A is correct.
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