JEE MAIN - Physics (2025 - 28th January Morning Shift - No. 6)

Find the equivalent resistance between two ends of the following circuit

JEE Main 2025 (Online) 28th January Morning Shift Physics - Current Electricity Question 2 English

$\frac{\mathrm{r}}{6}$

$\frac{\mathrm{r}}{3}$

$\frac{r}{9}$

JEE Main 2025 (Online) 28th January Morning Shift Physics - Current Electricity Question 2 English Explanation 1

Here, $${V_A} = {V_C}$$ & $${V_B} = {V_D}$$

So, JEE Main 2025 (Online) 28th January Morning Shift Physics - Current Electricity Question 2 English Explanation 2

So resistances are in parallel combination.

We know, $${1 \over {{R_p}}} = {1 \over {{R_1}}} + {1 \over {{R_2}}} + {1 \over {{R_3}}}$$

$$ \Rightarrow {1 \over {{R_p}}} = {3 \over r} + {3 \over r} + {3 \over r} = {9 \over r}$$

$$ \Rightarrow {R_p} = {r \over 9}$$