JEE MAIN - Physics (2025 - 28th January Evening Shift - No. 5)
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between $t = 0$ to $t = 4s$?
_28th_January_Evening_Shift_en_5_1.png)
11 m
30 m
13 m
10 m
Explanation
$\begin{aligned} & \text { Distance }=\text { Area under } \mathrm{v} \mathrm{v} / \mathrm{s} \text { t graph } \\ & \text { Distance }=\frac{1}{2} \times 2 \times 10+2 \times 10=30 \mathrm{~m}\end{aligned}$
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