JEE MAIN - Physics (2025 - 24th January Evening Shift - No. 7)
In photoelectric effect, the stopping potential $\left(\mathrm{V}_0\right) \mathrm{v} / \mathrm{s}$ frequency $(v)$ curve is plotted.
( h is the Planck's constant and $\phi_0$ is work function of metal )
(A) $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ is linear.
(B) The slope of $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ curve $=\frac{\phi_0}{\mathrm{~h}}$
(C) h constant is related to the slope of $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ line.
(D) The value of electric charge of electron is not required to determine h using the $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ curve.
(E) The work function can be estimated without knowing the value of $h$.
Choose the correct answer from the options given below :
Explanation
$$\begin{aligned} & \mathrm{hv}=\phi+\mathrm{KE}_{\max } \\ & \mathrm{KE}_{\max }=\mathrm{eV}_0 \\ & \mathrm{~V}_0=\frac{\mathrm{hv}-\phi}{\mathrm{e}} \end{aligned}$$
(A) $\mathrm{V}_0 \mathrm{v} / \mathrm{s} \mathrm{V}$ is linear correct
(B) Slope
$$\mathrm{v}_0=\left(\frac{\mathrm{h}}{\mathrm{e}}\right) \mathrm{v}-\frac{\phi}{\mathrm{e}} \text { Wrong }$$
Slope $\frac{\mathrm{h}}{\mathrm{e}}$
(C) Correct
(D) Incorrect
(E) Correct
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