JEE MAIN - Physics (2025 - 22nd January Morning Shift - No. 22)
Two soap bubbles of radius 2 cm and 4 cm , respectively, are in contact with each other. The radius of curvature of the common surface, in cm , is _________.
Answer
4
Explanation
We know, the radius of curvature of the common surface is given by,
$$r = \left| {{{{r_1}\,.\,{r_2}} \over {{r_1} - {r_2}}}} \right| = \left| {{{2\,.\,4} \over {2 - 4}}} \right| = \left| {{8 \over { - 2}}} \right| = 4$$
$$ \Rightarrow r = 4\,cm$$
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