JEE MAIN - Physics (2025 - 22nd January Morning Shift - No. 2)

If $B$ is magnetic field and $\mu_0$ is permeability of free space, then the dimensions of $\left(B / \mu_0\right)$ is
$\mathrm{MT}^{-2} \mathrm{~A}^{-1}$
$\mathrm{L}^{-1} \mathrm{~A}$
$\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^{-1}$
$\mathrm{LT}^{-2} \mathrm{~A}^{-1}$

Explanation

We know, for a solenoid, $$B = {\mu _0}nI$$

$$ \Rightarrow B = {\mu _0}{N \over L}I \Rightarrow {B \over {{\mu _0}}} = N\left( {{I \over L}} \right)$$

$$ \Rightarrow \left[ {{B \over {{\mu _0}}}} \right] = \left[ {{L^{ - 1}}A} \right]$$

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