JEE MAIN - Physics (2025 - 22nd January Evening Shift - No. 9)
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To obtain the given truth table, following logic gate should be placed at G :
NOR Gate
OR Gate
AND Gate
NAND Gate
None of the above
Explanation
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For NOR gate : $\overline{\mathrm{A}} \overline{\mathrm{B}}=\overrightarrow{\mathrm{A}}+\mathrm{B}$
$\therefore$ Truth table $$ \begin{array}{ccc} \mathrm{A} & \mathrm{~B} & \mathrm{Y} \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array}$$
$\therefore$ Bonus
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