JEE MAIN - Physics (2025 - 22nd January Evening Shift - No. 25)
A tube of length 1 m is filled completely with an ideal liquid of mass 2 M , and closed at both ends. The tube is rotated uniformly in horizontal plane about one of its ends. If the force exerted by the liquid at the other end is F then angular velocity of the tube is $\sqrt{\frac{\mathrm{F}}{\alpha \mathrm{M}}}$ in SI unit. The value of $\alpha$ is _________.
Answer
1
Explanation
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$$\begin{aligned} & \mathrm{F}=2 \mathrm{M} \omega^2 \frac{\ell}{2}=\mathrm{Mw}^2 \ell \\ & \omega=\sqrt{\frac{\mathrm{F}}{\mathrm{M} \ell}} \end{aligned}$$
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