JEE MAIN - Physics (2025 - 22nd January Evening Shift - No. 23)
A parallel plate capacitor of area $A=16 \mathrm{~cm}^2$ and separation between the plates 10 cm , is charged by a DC current. Consider a hypothetical plane surface of area $\mathrm{A}_0=3.2 \mathrm{~cm}^2$ inside the capacitor and parallel to the plates. At an instant, the current through the circuit is 6A. At the same instant the displacement current through $\mathrm{A}_0$ is __________ mA .
Answer
1200
Explanation
$$\begin{aligned}
& \mathrm{J}_{\mathrm{d}}=\frac{\mathrm{I}}{\mathrm{~A}}=\frac{6}{16} \\
& \therefore \text { I through small area }=\mathrm{J}_{\mathrm{d}} \times A^{\prime}=\frac{6}{16} \times 3.2= \\
& 1.2 \mathrm{~A}=1200 \mathrm{~mA}
\end{aligned}$$
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