JEE MAIN - Physics (2024 - 9th April Morning Shift - No. 3)
Explanation
To derive the dimensional formula of latent heat, we need to understand what latent heat actually refers to. Latent heat is the amount of heat absorbed or released by a substance during a change in its physical state (phase) that occurs without changing its temperature.
The formula for latent heat ($L$) is given by:
$Q = mL$
where:
$Q$ = Heat absorbed or released (with the dimension of energy $[\mathrm{ML}^2\mathrm{T}^{-2}]$),
$m$ = Mass of the substance ($[\mathrm{M}]$),
$L$ = Latent heat.
To find the dimensions of latent heat, we rearrange the formula to solve for $L$:
$L = \frac{Q}{m}$
Knowing the dimensions of $Q$ (energy, which is equivalent to work done, with dimensions $[\mathrm{ML}^2\mathrm{T}^{-2}]$) and $m$ (mass, with dimensions $[\mathrm{M}]$), we can substitute these into the equation to find $L$'s dimensions:
$L = \frac{[\mathrm{ML}^2\mathrm{T}^{-2}]}{[\mathrm{M}]}$
This simplifies to:
$L = [\mathrm{L}^2\mathrm{T}^{-2}]$
Therefore, the dimensional formula of latent heat is:
$L = [\mathrm{M}^0 \mathrm{L}^2 \mathrm{T}^{-2}]$
So, the correct option is:
Option C $ \left[\mathrm{M}^0 \mathrm{~L}^2 \mathrm{~T}^{-2}\right] $
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